General electronic configuration of outermost | vedclass

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(C) The given electronic configuration is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. Given $n = 4$ and $x = 5$. Substituting these values,we get the con

Vedclass · Accepted Answer

$25$

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(C) The given electronic configuration is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. Given $n = 4$ and $x = 5$. Substituting these values,we get the configuration: $1s^2 2s^2 2p^6 3s^2 3p^6 3d^5 4s^2$. The total number of electrons is $2 + 2 + 6 + 2 + 6 + 5 + 2 = 25$. Since the atom is neutral,the number of protons equals the number of electrons,which is $25$.

General electronic configuration of outermost and penultimate shell is $(n - 1)s^2 (n - 1)p^6 (n - 1)d^x ns^2$. If $n = 4$ and $x = 5$,then the number of protons in the nucleus will be:

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